
The sliding window technique is a powerful approach used to solve a variety of problems, especially those involving subarrays or substrings. Here are the key characteristics and criteria to identify if a problem can be effectively solved using the sliding window technique:
Characteristics of Sliding Window Problems
Contiguous Subarrays or Subsequences:
- The problem involves finding a subarray or substring with certain properties, such as a fixed length or a sum within a range.
Optimal Subarray/Subsequence:
- The problem requires finding an optimal subarray/subsequence, such as the longest, shortest, or one with the maximum/minimum sum/product.
Fixed or Variable Window Size:
- The sliding window can be either fixed in size (e.g., finding all subarrays of length k) or variable (e.g., finding the smallest subarray with a sum greater than a target).
Common Scenarios for Sliding Window Technique
Maximum/Minimum Sum Subarray of Fixed Length:
Problems where you need to find the maximum or minimum sum of a subarray of a fixed length.
def maxSumSubarray(nums, k): max_sum = current_sum = sum(nums[:k]) for i in range(k, len(nums)): current_sum += nums[i] - nums[i - k] max_sum = max(max_sum, current_sum) return max_sum
Longest Substring with K Distinct Characters:
Problems where you need to find the longest substring containing at most k distinct characters.
def lengthOfLongestSubstringKDistinct(s, k): char_map = {} left = 0 max_length = 0 for right in range(len(s)): char_map[s[right]] = char_map.get(s[right], 0) + 1 while len(char_map) > k: char_map[s[left]] -= 1 if char_map[s[left]] == 0: del char_map[s[left]] left += 1 max_length = max(max_length, right - left + 1) return max_length
Smallest Subarray with Sum Greater than a Given Value:
Problems where you need to find the smallest subarray with a sum greater than a given target.
def minSubArrayLen(target, nums): left = 0 current_sum = 0 min_length = float('inf') for right in range(len(nums)): current_sum += nums[right] while current_sum >= target: min_length = min(min_length, right - left + 1) current_sum -= nums[left] left += 1 return min_length if min_length != float('inf') else 0
Steps to Identify and Apply the Sliding Window Technique
Determine if the Problem Involves Subarrays or Subsequences:
- Check if the problem requires examining or optimizing properties of contiguous subarrays or subsequences.
Identify the Window Size:
- Determine if the window size is fixed or variable.
- For fixed-size windows, the problem often involves a specific length k.
- For variable-size windows, the problem usually has a condition to expand or contract the window.
Use a Two-Pointer Approach:
- Typically, the sliding window technique uses two pointers, left and right, to represent the current window.
- Adjust the pointers to expand or contract the window based on the problem’s requirements.
Maintain a Running Calculation:
- Keep track of the current state of the window (e.g., sum, product, or character count) as you slide the window across the array or string.
- Update the running calculation efficiently to reflect changes in the window.
Example Problem: Maximum Sum Subarray of Size K
Problem Statement: Given an array of integers and a number k, find the maximum sum of a subarray of size k.
Solution Using Sliding Window Technique:
def maxSumSubarray(nums, k):
max_sum = current_sum = sum(nums[:k]) # Step 1: Initialize window and calculate initial sum
for i in range(k, len(nums)): # Step 2: Slide the window across the array
current_sum += nums[i] - nums[i - k] # Step 3: Update the window sum
max_sum = max(max_sum, current_sum) # Step 4: Track the maximum sum found
return max_sum
# Sample Input
nums = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
k = 3
# Expected Output: 27 (subarray [8, 9, 10])
print(maxSumSubarray(nums, k))
By analyzing the problem’s characteristics and determining if the sliding window technique is applicable, you can effectively use this technique to solve a wide range of problems efficiently.